[tex]\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad
\begin{cases}
A=\textit{compounded amount}\to &\$10000\\
P=\textit{original amount deposited}\\
r=rate\to 9.5\%\to \frac{9.5}{100}\to &0.095\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus}
\end{array}\to &12\\
t=years\to &\frac{3}{2}
\end{cases}[/tex]
notice, the years are one and a half, or 3/2
solve for P, to see what the Principal should be
