dylancooper27
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a ball is thrown upward. its height ( h, in feet ) is modeled by the function h = -16t^2 + 64t+3, where t is the length of time ( in seconds ) that the ball has been in the air. what is the maximum height the ball reaches? a ball is thrown upward. its height ( h, in feet ) is modeled by the function h = -16t^2 + 64t+3, where t is the length of time ( in seconds ) that the ball has been in the air. what is the maximum height the ball reaches?

Respuesta :

Beginner123
To find the maximum height just simply find the vertex of  -16t^2 + 64t + 3 and to find the axis of symmetry or the x value of the vertex do -b/2a or -64/-32 = 2 in this situation. Plug in to get the y value -16(2)^2 + 64(2) + 3 = 67 Vertex (2,67) So the max height is 67 feet (takes 2 seconds to do so)

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