Given the exponential equation 3x = 27, what is the logarithmic form of the equation in base 10?

A. x = log base 10 of 3, all over log base 10 of 27
B. x = log base 10 of 27, all over log base 10 of 3
C. x = log base 2 of 3, all over log base 2 of 27
D. x = log base 2 of 10, all over log base 2 of 3

Respuesta :

the correct answer is letter B or the second option

Answer:

The exponential equation is in form of x= log base 10 of 27, all over log base 10 of 3

[tex]x=\dfrac{\log_{10}27}{\log_{10}3}[/tex]

B is correct

Step-by-step explanation:

Given: Exponential equation 3ˣ = 27

We need to write in logarithmic form with base 10

[tex]3^x=27[/tex]

First we will apply log both sides with base 10

[tex]\log_{10}3^x=\log_{10}27[/tex]

[tex]x\log_{10}3=\log_{10}27[/tex]                   [tex]\because \log a^m=m\log a[/tex]    

Now, we will divide by [tex]\log_{10}3[/tex] both sides

[tex]x=\dfrac{\log_{10}27}{\log_{10}3}[/tex]

Hence, The exponential equation is in form of x= log base 10 of 27, all over log base 10 of 3