Respuesta :
I hope this helps you
tgH=HJ/HK
angle H+angle K=90
H=K=45 degree
sin45=cos46 = square root of 2/2
tgH=HJ/HK
angle H+angle K=90
H=K=45 degree
sin45=cos46 = square root of 2/2
Answer:
C. [tex]sin(\angle H)=cos(\angle H)[/tex]
Step-by-step explanation:
Givens
[tex]\triangle HJK[/tex] is a right triangle.
[tex]m \angle J = 90\°[/tex]
[tex]tan (\angle H) = 1[/tex]
We this information, we can deduct that the opposite leg to [tex]\angle H[/tex] is JK, and the adjacent leg to [tex]\angle H[/tex] is JH. So, if [tex]tan (\angle H) = 1[/tex], this means that both legs are equal, because to result the tangent in 1, both legs have to be equal
[tex]tan(\angle H) = \frac{JK}{JH}=1[/tex]
Also, we can deduct that the angle [tex]\angle H[/tex] is equal to 45°, because when the tangent is equal to one unit, that means the triangle is symmetric, which means that its angles are 45°.
So, with knowing the measure of [tex]\angle H[/tex], we can find the rest of trigonometric reasons
[tex]sin(\angle H)=sin (45\°)=\frac{\sqrt{2} }{2} \\\\cos(\angle H)=cos(45\°)=\frac{\sqrt{2} }{2}[/tex]
Basically, this means that both reasons are equal
[tex]sin(\angle H)=cos(\angle H)[/tex]
Therefore, the right answer is C.