Answer:
The equation showing this situation is [tex]D=b^2-4ac=0[/tex]
Step-by-step explanation:
Given : A quadratic equation of the form [tex]ax^2 + bx + c=0[/tex] has one real number solution.
To find : Which could be the equation?
Solution :
A quadratic equation in form [tex]ax^2+bx+c=0[/tex] has a solution [tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex] called a quadratic formula in which the roots are one real,two real or no real is determine by discriminant factor.
Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :
1) If [tex]D=b^2-4ac>0[/tex] there are two real roots.
2) If [tex]D=b^2-4ac=0[/tex] there are one real roots.
3) If [tex]D=b^2-4ac<0[/tex] there are no real roots.
According to question,
A quadratic equation of the form [tex]ax^2 + bx + c=0[/tex] has one real number solution.
So, The equation showing this situation is [tex]D=b^2-4ac=0[/tex]
