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Two cards are randomly chosen without replacement from an ordinary deck of 52 cards. let b be the event that both cards are aces, let as be the event that the ace of spades is chosen, and let a be the event that at least one ace is chosen. find

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mreijepatmat
If I  understood the problem, the first should the Ace of spade, if so its probability is 1/52 & P(the second ace) 3/51


Tot Prob. = 1/52 * 3/51 =0.00113 or 0.113%