Respuesta :
you have been asking a lot to do with percents so I started working at leaning how to do them
65=100%
65/100=0.65
0.65=1%
3%=1.95
4.5%=2.925
65+1.95=66.95
66.95-2.925=64.025
64.025°F
I think I did it right
65=100%
65/100=0.65
0.65=1%
3%=1.95
4.5%=2.925
65+1.95=66.95
66.95-2.925=64.025
64.025°F
I think I did it right
Answer:
The daily average temperature in Darrtown in 2013 was 63.93725 °F
Step-by-step explanation:
The average daily temperature in 2011 was 65° F.
In 2012, the temperature increased by 3%. So, the amount of increased temperature [tex]=(65\times 3\%)= (65\times 0.03)= 1.95[/tex] °F
So, the temperature in 2012 [tex]=(65+1.95)= 66.95[/tex] °F
In 2013, the temperature is decreased by 4.5%. So, the amount of decreased temperature [tex]=(66.95\times 4.5\%)= (66.95\times 0.045)=3.01275[/tex] °F
So, the daily average temperature in 2013 [tex]=(66.95-3.01275)=63.93725[/tex] °F