Answer:
[tex]5\sqrt{3}=x[/tex]
Step-by-step explanation:
We are given an isosceles right triangle.
Refer the attached figure
ΔABC is an isosceles right triangle.
AB = BC = x (Let)
AC = Hypotenuse = 5√6 (Given)
Now using Pythagoras theorem
[tex]Hypotenuse^2=Perpendicular^2+Base^2[/tex]
[tex]AC^2=AB^2+BC^2[/tex]
[tex](5\sqrt{6})^2=x^2+x^2[/tex]
[tex]150=2x^2[/tex]
[tex]\sqrt{150}{2}=x^2[/tex]
[tex]75=x^2[/tex]
[tex]\sqrt{75}=x[/tex]
[tex]5\sqrt{3}=x[/tex]
Hence the leg of each isosceles right triangle when the hypotenuse is 5√6 is [tex]5\sqrt{3}[/tex].
Answer:
5 square root of 3
Step-by-step explanation:
im just right believe it
