Suppose Cone A and Cone B are similar solids with a ratio of 2:1 between the cones’ slant heights. Determine the ratio of the cones’ volumes.

2:1
4:1
6:1
8:1

Respuesta :

2:1
I think
not exactly certain

Answer: 8:1.

I actually came looking for the answer myself, and decided to show how to determine it is in fact an 8:1 ratio.

Step-by-step explanation:

  • Step 1 - Analyze

The wording is actually really important. Notice the phrase, "similar solids"? This is exactly the key piece of information needed. We can also see that:

- Cones have a 2:1 Ratio (a:b)

- We must find the ratio of the volumes compared to slant height.

  • Step 2 - Set up some cones

Let's set up two sample cones using the provided ratio 2:1. (A:B)

     - Cone B: Radius of 4, height of 12

     - Cone A: Radius of 2, height of 6.

We can find the length of the slant height using the pythagorean theorem since the height, radius, and slant height make a right triangle. (See image attached.)

*Pythagorean theorem = [tex]a^2+b^2=c^2[/tex]

A and B are the legs of the triangle, the radius and height. The slant height is c, the hypotenuse.

  • Step 3 - Use the theorem

Cone A: [tex]6^2+2^2=l^2\\36+4=l^2\\40 = l^2\\\sqrt{40} = l\\4\sqrt{10}  = l\\[/tex]

Cone B: [tex]12^2+4^2=l^2\\144+16=l^2\\ 160=l^2\\\sqrt{160}=l\\4\sqrt{10}  = l[/tex]

Ok cool, we got the slant heights now.  By looking at that we can confirm there is a 2:1 ratio happening here. Now, we want to solve for volume.

  • V O L U M E!

The equation for volume of a cone is: [tex]\frac{1}{3} \pi r^2h[/tex]   where r = radius and h = height. Let's use 3.14 as pi.

  - Now just substitute and solve.

Cone A: [tex]\frac{1}{3}*3.14*2^2*6 = V\\\frac{1}{3} *3.14*24\\\frac{1}{3}*75.36\\25.12 = V[/tex]

Cone B:  [tex]\frac{1}{3}*3.14*4^2*12 = V\\\frac{1}{3} *3.14*192\\\frac{1}{3}*602.88\\200.96 = V[/tex]

  • Step 4 - Compare

Divide 200.96 by 25.12.  You get 8! That means the ratio compared to volume is 8:1.

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  • Hope this helped!~ A thank you or brainly would be much appreciated.

Have a great day!

        - Astro