1.
4 passengers in total so additional passenger is 3 = [tex]1.5*3=4.5[/tex].
Since fare is broken down into [tex]\frac{1}{5}[/tex] parts, we need to figure out how many of these [tex]\frac{1}{5}[/tex] parts are there in 11.8 miles.
There are [tex]\frac{11.8}{\frac{1}{5}}=59[/tex] parts.
First [tex]\frac{1}{5}[/tex] mile is $0.75
Remaining 59 - 1 = 58 parts are worth $0.55 each. So total is [tex]58*0.55=31.9[/tex] dollars.
Grand total with 4 passengers and 11.8 miles is [tex]4.5+31.9+0.75=37.15[/tex] dollars.
Fourth choice is correct.
2.
2 passengers in total so additional passenger is 1 = [tex]1.5*1=1.5[/tex].
Like before, how many [tex]\frac{1}{5}[/tex] parts are ther in 5.8 miles?
[tex]\frac{5.8}{\frac{1}{5}}=29[/tex] parts
First [tex]\frac{1}{5}[/tex] mile is $0.75
Remaining 29 - 1 = 28 parts are worth $0.55 each. So total is [tex]28*0.55=15.4[/tex] dollars.
Now, the Total is [tex]1.5+0.75+15.4=17.65[/tex].
There is a 15% additional tip to that.
[tex](0.15)(17.65)=2.65[/tex] dollars is the tip.
Grand total with 2 passengers, 5.8 miles, and 15% tip is [tex]1.5+0.75+15.4+2.65=20.3[/tex] dollars.
Second choice is correct.
ANSWER:
1. $37.15
2. $20.30
