On the following dartboard, the radius of the bulls-eye (area A) is 4 inches. The radius of each concentric circle is 4 inches more than the circle inside it. If a person throws randomly onto the dartboard, what is the probability that the dart will hit in area B ?

Respuesta :

The probability that the dart will hit in area B is 3/4

How to determine the probability?

The given parameters are:

Area A = 4 inches (radius)

Dartboard  = 8 inches (radius)

The area of area A is:

A = πr^2

This gives

A = π * 4^2

A = 16π

The area of the dartboard is:

Dartboard = πR^2

This gives

Dartboard = π * (4 + 4)^2

Dartboard = 64π

So, the area B is:

B = Dartboard - A

This gives

B = 64π - 16π

Evaluate the difference

B = 48π

The probability that the dart will hit in area B is:

P = B/Dashborad

This gives

P = 48π/64π

Evaluate the quotient

P = 3/4

Hence, the probability that the dart will hit in area B is 3/4

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https://brainly.com/question/251701

Answer:3/4

Step-by-step explanation: