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taskmasters
I found an image that corresponds to the above question.
The shape was a rectangle. Its width is 7 units, its length is x.
The shaded area of the rectangle forms a trapezoid.

Area of a trapezoid = [(a+b)/2] * h

63 sq. units = (7+x)/2 * 7
63/7 = (7+x)/2
9 = (7+x)/2
9*2 = 7 + x
18 = 7 + x
18 - 7 = x
11 = x

The value of x is 11 units. It is the length of the rectangle.

Area of the trapezoid = (a+b)/2 * h
63 = (7+11)/2 * 7
63 = 18/2 * 7
63 = 9 * 7
63 = 63 
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shubhamchouhanvrVT

The value of x is 11 units. It is the length of the rectangle.

What is the area of the rectangle?

The shape was a rectangle. Its width is 7 units, its length is x.

The shaded area of the rectangle forms a trapezoid.

Area of a trapezoid

[tex]= [\dfrac{(a+b)}{2}] \times h[/tex]

[tex]63 = \dfrac{(7+x)}{2} \times 7[/tex]

[tex]\dfrac{63}{7} =\dfrac{(7+x)}{2}[/tex]

[tex]9 =\dfrac{ (7+x)}{2}[/tex]

[tex]9\times 2 = 7 + x[/tex]

[tex]18 = 7 + x[/tex]

[tex]18 - 7 = x[/tex]

[tex]11 = x[/tex]

The value of x is 11 units. It is the length of the rectangle.

To know more about rectangles follow

https://brainly.com/question/25292087

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