Using the technique in the model above, find the missing side in this 30°-60°-90° right triangle.


Short = 5 , hypotenuse = 10
Long =


Please help I am really confused

Using the technique in the model above find the missing side in this 306090 right triangle Short 5 hypotenuse 10 Long Please help I am really confused class=

Respuesta :

Is it trigonometry?
In that case take 30 degree as our reference point, then the long side will be hypotenuse*cos 30 which is 10*1/2*sqrt(3)

You can always use the rule: front=hypotenuse*sin of the degree
 Side=hypotenuse*cos of the degree

Answer:

The side of long is, [tex]5\sqrt{3}[/tex] units

Step-by-step explanation:

This is the special right angle triangle [tex]30^{\circ} -60^{\circ}-90^{\circ}[/tex] as shown in the figure.

  • The side opposite the 30° angle is always the shortest because 30 degrees is the smallest angle.
  • The side opposite the 60° angle will be the longer side, because 60 degrees is the mid-sized degree angle in this triangle.
  • Finally , the side opposite the 90° angle will always be the largest side(Hypotenuse) because 90 degrees is the largest angle.

In 30°−60°−90° right triangle,

the length of the hypotenuse is twice the length of the shorter side,

also,  the length of the longer side is [tex]\sqrt{3}[/tex] times the length of the shorter leg.

Given: length of short(S) = 5 units , hypotenuse(H) = 10 units

To find length of long side(L)

Then,

Using above statement;

length of longer sides(L) = [tex]\sqrt{3} \times S[/tex]

Substitute the values we get;

[tex]L = \sqrt{3} \times 5 = 5\sqrt{3}[/tex] units