1.
[tex]a^2+b^2=c^2[/tex]
So...
[tex]a^2+9=225[/tex]
[tex]a = \sqrt{216} = 6 \sqrt{6} [/tex]
2.
In right triangles, the formula I used in number 1 can be used to determine if a triangle is a right triangle.
[tex]7^2+9^2=12^2[/tex]
If this is true, the triangle is a right triangle.
[tex]49+81=144?[/tex]
No, 49+81=130, so the triangle is not a right triangle..
For number 3, use the Pythagorean theorem to find side NP so we can calculate the area.
[tex]a^2+16^2=25^2[/tex]
[tex]a^2= 369[/tex]
[tex]a = \sqrt{369} [/tex]
Can you calculate the area now?
I hope this helps clear things up. If you still need assistance, leave a comment. :)
