Answer:
m∠ACE=[tex]40\°[/tex]
Step-by-step explanation:
we know that
The measurement of the external angle is the semi-difference of the arcs which comprises
In this problem
m∠ACE represent a external angle
so
m∠ACE=[tex]\frac{1}{2}(minor\ arc\ AE- minor\ arc\ BD)[/tex]
Find the minor arc AE
[tex]minor\ arc\ AE=360\°-minor\ arc\ AB-minor\ arc\ BD-minor\ arc\ ED[/tex]
substitute the values
[tex]minor\ arc\ AE=360\°-115\°-25\°-115\°=105\°[/tex]
m∠ACE=[tex]\frac{1}{2}(105\°-25\°)[/tex]
m∠ACE=[tex]40\°[/tex]
