Respuesta :
All types of EM radiation travel at the same velocity. Yes, Chayse's results were reasonable. Ultraviolet rays are a type of electromagnetic radiation.
Electromagnetic Spectrum :
It is the range of all different types of electromagnetic radiation from Gamma rays to radio waves.
The velocity of all kinds of EM waves is the same. The velocity of the radiation is the product of the frequency and wavelength.
[tex]\bold{V = \lambda f}\\[/tex]
Where,
[tex]\lambda[/tex] - wavelength = [tex]\bold{ 1.96 \times 10^-^8 m }[/tex]
f - frequency = [tex]\bold{ 1.53 \times 10^1^6 Hz}[/tex]
Put the value in the formula,
[tex]\bold{ V = (1.96 \times 10^-8)(1.53 \times 10^1^6 Hz )}\\\\\bold{ V = 3 \times 10^8}[/tex]
Since the velocity of EM wave is [tex]3 \times 10^8[/tex]. Therefore, the results of Chayse are reasonable.
To know more about the electromagnetic spectrum, refer to the link:
https://brainly.com/question/23727978
Answer:
Sample Response: Yes, Chayse's results are reasonable because all parts of the electromagnetic spectrum travel at the speed of light. By multiplying his results for frequency and wavelength, I can see that the velocity of the UV ray is close to the speed of light.
Explanation:
