Respuesta :
The final pressure is 0.612 atm.
What is ideal gas?
The gas having following properties are belong to an ideal gas.
- The molecule of ideal gas occupy negligible space.
- There are no interaction between ideal gas molecules.
- The ideal gas consequently obeys the gas law equation.
The ideal gas law equation is written as.
PV = nRT
[tex]P_{1} V_{1} = nRT_{1}[/tex]
[tex]P_{1} V_{1}/ T_{1}=P_{2} V_{2}/ T_{2}[/tex] ... (i)
And,
[tex]P_{2} V_{2} = nRT_{2}[/tex]
[tex]R =P_{2} V_{2}/ nT_{2}[/tex] ...... (ii)
By combining, equation i and ii, we get.
[tex]P_{1} V_{1}/ T_{1}=P_{2} V_{2}/ T_{2}[/tex] (iii)
- P is pressure of the gas
- V is volume occupied by the gas
- n is number of moles of the gas.
- T is temperature
- R is universal gas constant
Calculation,
Given, Initial temperature in kelvin([tex]T_{1}[/tex]) = -20C = -20 + 273 = 253K
Final temperature in kelvin ([tex]T_{2}[/tex]) = 57 = 57+273 = 320K
Initial presure ([tex]P_{1}[/tex]) = 0.109 atm
Initial volume([tex]V_{1}[/tex]) = 2L
Final volume([tex]V_{2}[/tex]) = 4.5L
Putting the values all data given in equation. we get,
0.109 × 2/253 = P2 × 4.5/320
[tex]P_{1}[/tex] = 0.109×2×320/253×4.5
[tex]P_{1}[/tex] = 0.0612 atm
To learn more about Ideal gas here.
https://brainly.com/question/13821925
#SPJ2
