Use the drop-down menus to complete the statements about the function p(x) = x(x – 1) + 1. The value of a is . The value of b is . The value of c is . The value of the discriminant is . The quadratic function will intersect the x-axis times.

Respuesta :

Answer: The value of a is 1. The value of b is -1. The value of c is 1. The value of the discriminant is -3. The quadratic function will not intersects the  x-axis.

Explanation:

The standard form of a quadratic equation is,

[tex]p(x)=ax^2+bx+c[/tex]

The given function is,

[tex]p(x)=x(x-1)+1[/tex]

It can be written as,

[tex]p(x)=x^2-x+1[/tex]

By comparing this equation with the standard form of quadratic equation. we get,

[tex]a=1[/tex]

[tex]b=-1[/tex]

[tex]c=1[/tex]

The formula for discriminant is,

[tex]D=b^2-4ac[/tex]

[tex]D=(-1)^2-4(1)(1)[/tex]

[tex]D=1-4[/tex]

[tex]D=-3[/tex]

The value of the discriminant is -3.

If D<0, it means the function have no real roots.

If D=0, it means function have one real roots.

If D>0, it means function have two real roots.

Since D<0 it means the function have no real roots. So the function will not intersect the x-axis at any point.

The value of a is 1.

The value of b is -1.

The value of the c is 1.

The value of the discriminant is -3.

The function will not intersect the x-axis at any point.

Given that

Use the drop-down menus to complete the statements about the function p(x) = x(x – 1) + 1.

We have to determine

The value of a is.

The value of b is.

The value of c is.

The value of the discriminant is.

The quadratic function will intersect the x-axis times.

According to the question

The given equation is,

[tex]\rm p(x) = x(x - 1) + 1 [/tex]

To determine the discrimination of the given function expand the function.

Then,

[tex]\rm p(x) = x(x - 1) + 1\\ \\ p(x) = x^2-x+1[/tex]

On comparing with the standard quadratic equation,

[tex]\rm ax^2+bx+c=0[/tex]

The value of a is 1.

The value of b is -1.

The value of the c is 1.

The discrimination of the quadratic equation is given by;

[tex]\rm Discriminate = b^2-4ac\\ \\ Discriminate = (-1)^2-4 \times 1 \times 1\\ \\ Discriminate =1 -4\\ \\ Discriminate =-3[/tex]

The value of the discriminant is -3.

Here the value of D<0 means the function has no real roots.

So the function will not intersect the x-axis at any point.

To know more about Discriminate click the link given below.

https://brainly.com/question/15884086