Ms. Peterson wrote the expression below on the chalkboard for her class. she asked the students to write an equivalent expression using no more than one set of parentheses.
4(3x + 5y + 2z) + 3(x-z)

A. Tom Wrote 12x + 20y + 8z
B. Jenna Wrote 5(3x + 4y + z)
C. Chris Wrote 15x + 20y - 5z

jenna is correct

when the brackets are expanded you get
12x + 20y + 8z + 3x - 3z

simplify that to get 15x + 20y + 5z

when factorised, you find a HCF (highest common factor) in this case 5, and divide them all by it. 5 is then placed outside the bracket to create Jennas answer of
5(3x + 4y +z)

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Ms. Peterson wrote the expression below on the chalkboard for her class. she asked the students to write an equivalent expression using no more than one set of parentheses. 4(3x + 5y + 2z) + 3(x-z) A. Tom Wrote 12x + 20y + 8z B. Jenna Wrote 5(3x + 4y + z) C. Chris Wrote 15x + 20y - 5z

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Ms. Peterson wrote the expression below on the chalkboard for her class. she asked the students to write an equivalent expression using no more than one set of parentheses.
4(3x + 5y + 2z) + 3(x-z)

A. Tom Wrote 12x + 20y + 8z
B. Jenna Wrote 5(3x + 4y + z)
C. Chris Wrote 15x + 20y - 5z