carolynalee
contestada

There are two spinners. The first spinner has three equal sectors labeled 1, 2, and 3. The second spinner has four equal sectors labeled 3, 4, 5, and 6. The spinners are spun once.

How many outcomes do not show an odd number on the first spinner and show a 3 on the second spinner?

A. 1
B. 2
C. 3
D. 5

Respuesta :

anthonybailey12
it would be A because there is only 1 chance on each board

Answer: Option'A' is correct.

Step-by-step explanation:

Since we have given that

The first spinner has three equal sectors labeled i.e.

1, 2, 3

The second spinner has four equal sectors labeled i.e.

3, 4, 5, 6

So, the sample space will be

[tex]\{(1,3),(1,4),(1,5),(1,6),(2,3),(2,4),(2,5),(2,6),(3,3),(3,4),(3,5),(3,6)\}[/tex]

We need to find the number of outcomes which do not show an odd number on the first spinner and show a 3 on the second spinner.

i.e. (2,3)

So, there are only one such outcome .

Hence, Option'A' is correct.

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