Answer:
The compound’s molecular formula is C₆H₆, formula that belongs to benzene.
Explanation:
In the first place it is possible to determine the quantity of moles that represent 60.0 g of C and 5.05 g of H. For this, in the periodic table it is possible to observe that the atomic mass of C is 12 g/mol and of H is 1.01 g/mol.
Applying the rule of three, then it is possible to determine the amounts of moles mentioned:
- [tex]moles of C=\frac{60 g*1 mol}{12 g} = 5[/tex]
- [tex]moles of H=\frac{5.05 g*1 mol}{1.01 g} = 5[/tex]
This indicates that the molar ratio between C and H (C: H) is 5: 5, therefore, it is the same as saying that the ratio between C: H is 1: 1.
Then the molecular formula is assumed to be CnHn, where n is the present amount of each element, that since the ratio is 1: 1 the amount of C and H is the same. So, to find the molar mass of the compound you must calculate it as follows, taking into account the molar mass of each element, the amount present in the compound and its molar mass:
12 g / mol * n + 1 g / mol * n = 78.12 g / mol.
Solving this you get:
n*(12 g/mol + 1 g/mol)=78.12 g/mol
n*13 g/mol=78.12 g/mol
[tex]n=\frac{78.12 g/mol}{13 g/mol} \\[/tex]
n≅6
The compound’s molecular formula is C₆H₆, formula that belongs to benzene.
