If molten magnesium bromide (MgBr) is split by electrolysis, which of the following reactions occurs at the anode?

Question 1 options:

2Br2 (g) --> 2Br (l) + 2e-

2Mg+ (l) --> 2Mg+ (l) + 2e-

2Br- (l) --> Br2 (g) + 2e-

2Mg+ (l) + 2e- --> 2Mg (l)

In this electrolytic cell, the oxidation occurs at anode which is a positive electrode and reduction occurs at cathode which is a negative electrode.

For example : On passing electricity in the molten [tex]MgBr_2[/tex].

The two half-reaction equation are :

Reduction : [tex]Mg\rightarrow Mg^{2+}+2e^-[/tex] (cathode)

Oxidation : [tex]Br_2+2e^-\rightarrow 2Br^-[/tex] (anode)

The balanced chemical reaction will be,

[tex]MgBr_2\rightarrow Mg^{2+}+2Br^-[/tex]

Hence, the correct option is, [tex]Br_2+2e^-\rightarrow 2Br^-[/tex]

If molten magnesium bromide (MgBr) is split by electrolysis, which of the following reactions occurs at the anode? Question 1 options: 2Br2 (g) --> 2Br (l) + 2e- 2Mg+ (l) --> 2Mg+ (l) + 2e- 2Br- (l) --> Br2 (g) + 2e- 2Mg+ (l) + 2e- --> 2Mg (l)

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If molten magnesium bromide (MgBr) is split by electrolysis, which of the following reactions occurs at the anode?

Question 1 options:

2Br2 (g) --> 2Br (l) + 2e-

2Mg+ (l) --> 2Mg+ (l) + 2e-

2Br- (l) --> Br2 (g) + 2e-

2Mg+ (l) + 2e- --> 2Mg (l)