Step-by-step explanation:
Refer the figure.
Horizontal distance = AB = 2800 ft
Angle = ∠B = 10°
We need to find AC that is h.
We have
[tex]tanB=\frac{AC}{AB}\\\\tan10=\frac{h}{2800}\\\\h=2800\times tan10=493.72ft[/tex]
Vertical distance gained from takeoff = 493.72 ft