PLEASE HELP. A jar contains 4 red marbles numbered 1 to 4 and 6 blue marbles numbered 1 to 6. A marble is drawn at random from the jar. Find the probability of the given event.

(a) The marble is red then your answer is?
(b) The marble is odd numbered then your answer is?
(c) The marble is red or odd numbered then your answer is?
(d) The number is blue or even numbered then your answer is?

A. There are a total of ten marbles, with four being red, so answer is 4/10, or 2/5
B. The numbers are 1,2,3,4,1,2,3,4,5,6 and five are odd, so answer is 5/10, or 1/2
C. Combine the above answers (because it is either red or odd numbered), so answer is 9/10
D. There are six blue, so blue probability is 6/10, and even is five, so answer is 5/10, total answer is 11/10. This will definitely happen.

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Yogeshkumari Yogeshkumari · Answer 2 · 2022-06-22T05:32:35+02:00

The required probabilities are

a. Probability of getting red marble [tex]\frac{4}{10}.[/tex]

b. Probability of getting odd numbered marbles [tex]P(B)=\frac{5}{10}[/tex]

c. Probability of getting marble is red or odd numbered [tex]= \frac{9}{10}[/tex]

d. Probability of getting marble is blue or even [tex]= \frac{11}{10}[/tex]

What is probability?

" Probability is defined as the ratio of the number of favourable outcomes to the total number of outcomes."

Formula used

Probability = [tex]\frac{(Number of favourable outcomes)}{(total number of outcomes)}[/tex]

According to the question,

Jar contains 4 red balls numbered 1,2,3,4

[tex]R_{1}, R_{2},R_{3},R_{4},[/tex]

Jar contains 6 blue balls numbered 1,2,3,4,5,6

[tex]B_{1}, B_{2},B_{3},B_{4}, B_{5}, B_{6}[/tex]

Total number of balls in a jar =10

Number of red balls = 4

Number of blue balls = 6

Substitute the values in the formula of probability we get,

a. Probability of getting red marble [tex]P(A)=\frac{4}{10}[/tex]

b. Possible outcomes are = [tex]R_{1}, R_{3},B_{1}, B_{3},B_{5},[/tex]

Probability of getting odd numbered marbles [tex]P(B)=\frac{5}{10}[/tex]

c. Probability of getting marble is red or odd numbered [tex]= P(A) +P(B)[/tex]

[tex]=\frac{4}{10} +\frac{5}{10}[/tex]

[tex]= \frac{9}{10}[/tex]

d. Probability of getting marble is blue or even

= probability of getting blue + probability of getting even

[tex]= \frac{6}{10}+\frac{5}{10}[/tex]

[tex]= \frac{11}{10}[/tex]

Hence, the required probabilities are

a. Probability of getting red marble [tex]\frac{4}{10}.[/tex]

b. Probability of getting odd numbered marbles [tex]P(B)=\frac{5}{10}[/tex]

c. Probability of getting marble is red or odd numbered [tex]= \frac{9}{10}[/tex]

d. Probability of getting marble is blue or even [tex]= \frac{11}{10}[/tex]

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