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Does the series converge or diverge? If it converges what is the sum?

Infinite sigma n=1 -4 (-1/2)^n-1
I know the answer is yes it converges and the sum= -8/3 but I actually want to learn how to do it not just get answers please help!

Does the series converge or diverge If it converges what is the sum Infinite sigma n1 4 12n1I know the answer is yes it converges and the sum 83 but I actually class=

Respuesta :

The geometric series [tex]\sum\limits^{\infty}_{n=1} -4(-\frac 12)^{n-1} = -\frac 83[/tex]  converges

How to determine the series type?

The series is given as:

[tex]\sum\limits^{\infty}_{n=1} -4(-\frac 12)^{n-1} = -\frac 83[/tex]

The above series is a geometric series with the following common ratio

[tex]r = -\frac 12[/tex]

Series that have a common ratio whose absolute value is less than 1 would converge.

i.e.

|r| < 1

Because |-1/2| < 1, then we can conclude that the series would converge

Read more about series at:

https://brainly.com/question/7882626

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