Respuesta :
the equation of a line that passe through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)
find slope firsrt
slope betwen (x1,y1) and (x2,y2) is (y1-y2)/(x1-x2)
points (-1,-4) and (3,2)
slope=(-4-2)/(-1-3)=-6/-4=6/4=3/2
a point is either (-1,-4) or (3,2)
so the equations possible are
y+4=(3/2)(x+1) and
y-2=(3/2)(x-3)
y-y1=m(x-x1)
find slope firsrt
slope betwen (x1,y1) and (x2,y2) is (y1-y2)/(x1-x2)
points (-1,-4) and (3,2)
slope=(-4-2)/(-1-3)=-6/-4=6/4=3/2
a point is either (-1,-4) or (3,2)
so the equations possible are
y+4=(3/2)(x+1) and
y-2=(3/2)(x-3)
(-1,-4), (3,2)
Find the slope :
m = 2 + 4 / 3 + 1
m = 6/4
Simplify.
m = 3/2
So, plug in everything into the point-slope form equation.
Point-slope form : y - y₁ = m(x - x₁)
y + 4 = 3/2x + 1
~Hope I helped!~
Find the slope :
m = 2 + 4 / 3 + 1
m = 6/4
Simplify.
m = 3/2
So, plug in everything into the point-slope form equation.
Point-slope form : y - y₁ = m(x - x₁)
y + 4 = 3/2x + 1
~Hope I helped!~