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Using a sixteen-sided number cube, what is the probability that you will roll an even number or an odd prime number? The number 1 isn't an odd prime. Round to three decimals.

Respuesta :

1. Let a: rolling an even number, b: rolling an odd prime number

2. a={2, 4, 6, 8, 10, 12, 14, 16}, b={3, 5, 7, 11, 13}

3. So n(a)=8, n(b)=5 , n(Sample Space)=n(S)=16

4. Since a and b are mutually exclusive events, that means they have no common elements, P(a or b)=P(a)+P(b)=[tex] \frac{n(a)}{n(S)}+ \frac{n(b)}{n(S)}= \frac{8}{16}+ \frac{5}{16}= \frac{13}{16}= 0.813 [/tex]


onyebuchinnaji

When using a sixteen-sided number cube, the probability that you will roll an even number or an odd prime number is 0.813.

Even number

The possible even numbers obtained is given as;

Even = {2, 4, 6, 8, 10, 12, 14, 16}, = 8 numbers

Odd prime number

The possible odd prime numbers obtained is given as;

odd prime numbers = {3, 5, 7, 11, 13} = 5 numbers

Total sample space = count from 1 to 16

Total sample space = 16

Probability of rolling even number or odd prime number;

P(E or OP) = 8/16 + 5/16

P(E or OP) = 0.813

Thus, when using a sixteen-sided number cube, the probability that you will roll an even number or an odd prime number is 0.813.

Learn more about probability here: https://brainly.com/question/251701

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