Respuesta :
H: {1,2,3,4,5,6}
or
T: {1,2,3,4,5,6)
n(S) = 2 x 6 =12
n(E) = {(H,5), (H,6)} = 2
[tex]P(E)=\frac{n(E)}{n(S)}=\frac{2}{12}=\frac{1}{6}[/tex]
Answer: 1/6
or
T: {1,2,3,4,5,6)
n(S) = 2 x 6 =12
n(E) = {(H,5), (H,6)} = 2
[tex]P(E)=\frac{n(E)}{n(S)}=\frac{2}{12}=\frac{1}{6}[/tex]
Answer: 1/6