Respuesta :
Answer:
The correct option will be: Rectangle C (Width= 6 and Length= 10)
Step-by-step explanation:
Suppose, the length of the original photograph is [tex]x[/tex] inches and width is [tex]y[/tex] inches.
Hiroto reduces the photograph by 0.5 by scanning it onto his computer.
So, the length of the scanned image [tex]=0.5x[/tex] inches and width [tex]=0.5y[/tex] inches.
Given that, the length and width of the image on the screen are 5 inches and 3 inches respectively. That means.........
[tex]0.5x=5\\ \\ x=\frac{5}{0.5}=10\\\\\\ and\\ \\ 0.5y=3\\ \\ y=\frac{3}{0.5}=6[/tex]
So, the rectangle [tex]C[/tex] represents the original photograph, which has width as 6 inches and length as 10 inches.
Answer:
The correct option is C.
Step-by-step explanation:
Let the original size of the photograph be x by y.
It is given that Hiroto reduces a rectangular photograph by 0.5 by scanning it onto his computer.
The new size of the photograph is 0.5x by 0.5y.
It is given that the image on the screen measures 3 inches by 5 inches.
[tex]0.5x=3[/tex]
Divide both sides by 0.5.
[tex]x=6[/tex]
[tex]0.5y=5[/tex]
Divide both sides by 0.5.
[tex]y=10[/tex]
Therefore the original size of the photograph is 6 by 10. Option C is correct.
