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A customer has six (6) $1 bills, three (3) $5 bills, four (4) $10 bills, seven (7) quarters, ten (10) dimes, seven (7) nickels, and nine (9) pennies. the customer buys a pair of shoes for $49.86. based on the combination of bills and coins the customer has, what are the least number of bills and coins the customer can give the cashier in order to buy the shoes for the exact amount and not require any change back? 8 bills, 5 coins 8 bills, 6 coins 9 bills, 5 coins 9 bills, 8 coins 10 bills, 7 coins

Respuesta :

the answer in 9 bills and 5 coins he woulds give him 4-$10, 1-$5 4-$1 and3-$.25, dime and 4 pennies

Solution:

The Combination of Coins and Bills possessed by customer =  Six (6) $1 bills, three (3) $5 bills, four (4) $10 bills, seven (7) quarters, ten (10) dimes, seven (7) nickels, and nine (9) pennies.

Price of  pair of shoes=$ 49.86

1 Quarter = 0.25 of a dollar, 1 Dime = 0.10 of a dollar, 1 Nickel = 0.05 of a dollar, 1 Penny = 0.01 of a dollar

→→$49.86= [ four (4) $10 bills + One (1) $5 bills + four (4) ,$1 bills]+[Three (3) quarters + One(1) Dime +1, Penny]= 5 Coins and 9 Bills→→Option D

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