The equation of the reflected line is y+x=6, the point lies on (2,4).
Given to us
y-x=4
What is the slope of two perpendicular lines?
Since it is given that the light and its reflection are intersecting each other at an angle of 90°, therefore, both the lines are perpendicular to each other.
We know that for two perpendicular lines, their slope is equal to each other, and their slopes will be negative and inverse.
[tex]y-x=4\\y=x+4\\[/tex]
Since the slope of the light ray is equal to 1, the slope of its inverse will be, -1.
Reflected ray,
[tex]y= -x+c\\y+x=c[/tex]
Therefore, the slope of the equation is y+x=c.
Substitute the point (1,5),
[tex]y+x\\= 5+1\\=6[/tex]
Therefore, the equation of the line will be y+x=6
What are the points that do not lie on the reflected ray.?
Since the point that does not satisfy this equation is (-2,-8), therefore, this point will not lie on the reflected ray.
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