PLEASE HELP! Patel is solving 8x2 + 16x + 3 = 0. Which steps could he use to solve the quadratic equation? Check all that apply. 8(x2 + 2x + 1) = –3 + 8 x = –1 x = –1 8(x2 + 2x + 1) = 3 + 1 8(x2 + 2x) = –3

Respuesta :

we have

[tex]8x^{2}+16x+3=0[/tex]

Step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

[tex]8x^{2}+16x=-3[/tex]

Step 2

Factor the leading coefficient

[tex]8(x^{2}+2x)=-3[/tex]

Step 3

Complete the square. Remember to balance the equation by adding the same constants to each side.

[tex]8(x^{2}+2x+1)=-3+8[/tex]

[tex]8(x^{2}+2x+1)=5[/tex]

Step 4

Rewrite as perfect squares

[tex]8(x+1)^{2}=5[/tex]

[tex](x+1)^{2}=\frac{5}{8} \\\\(x+1)=(+/-)0.79\\\\x1=0.79-1=-0.21\\\\x2=-0.79-1=-1.79[/tex]          

therefore

the answer is

[tex]8(x^{2}+2x)=-3[/tex]

[tex]8(x^{2}+2x+1)=-3+8[/tex]


The steps are used to solve the equation are as follows

8(x2 + 2x) = –3

And 8(x2 + 2x + 1) = –3 + 8.

Roots of the quadratic equation

The roots of the quadratic equation can be determined by using the factorization following all the steps given below.

Given information

Patel is solving 8x2 + 16x + 3 = 0.

The quadratic equation solving by factorization method;

[tex]\rm 8x^2+16x+3=0\\\\ 8(x^2+2x)+3=0\\\\ 8(x^2+2x)=-3\\\\8(x^2+2x+1)=-3+8\\\\8x^2+16x=-3+8-8\\\\8x^2+16x=-3[/tex]

Hence, the steps are used to solve the equation are as follows 8(x2 + 2x) = –3 and 8(x2 + 2x + 1) = –3 + 8.

To know more about quadratic equations click the link given below.

brainly.com/question/2263981