Answer:
[tex](x-2)+(y+3)=3^{2}[/tex]
Step-by-step explanation:
The equation of a circle when the center of the circumference is on the origin of the graph is:
[tex]x^{2} +y^{2} =r^{2}[/tex]
And when the center is in any other point of the graph it´s expressed i like this:
[tex](x-h)^{2} +(y-k)^{2} =r^{2}[/tex]
So h and k are the coordinates of the center of the circumference, having that the center of the circle is: (2,-3) we know that h=2 and k is=-3, so if we put the values on the formula the equation would look like this:
[tex](x-h)^{2} +(y-k)^{2} =r^{2}[/tex]
[tex](x-(2))^{2} +(y-(-3))^{2} =3^{2}[/tex]
[tex](x-2)^{2} +(y+3)^{2} =3^{2}[/tex]
That´s the equation of a circle with center (2,-3) and a radius of 3.
