Respuesta :
KE = ½mv²
1.1 x 10^9 = ½ x 8 x 10^4 v²
v² = 2.75 x 10^4
v ≈ 165.8 m/s
1.1 x 10^9 = ½ x 8 x 10^4 v²
v² = 2.75 x 10^4
v ≈ 165.8 m/s
The speed of the airliner is 165.83 m/s.
Kinetic Energy
The energy stored within an object during its motion is called the kinetic energy of the object. The kinetic energy of an object can be given as below.
[tex]KE = \dfrac {1}{2} mv^2[/tex]
Where KE is the kinetic energy, m is the mass and v is the velocity of the object.
Given that the mass of the airliner is 8.0 × 10^4 kg and its kinetic energy is 1.1 × 10^9 J. Hence the speed of the airliner can be calculated as given below.
[tex]1.1\times 10^9 = \dfrac{1}{2} \times 8.0\times 10^4\times v^2[/tex]
[tex]v^2 = 27500[/tex]
[tex]v = 165.83 \;\rm m/s[/tex]
Hence we can conclude that the speed of the airliner is 165.83 m/s.
To know more about kinetic energy, follow the link given below.
https://brainly.com/question/999862.
