A flashlight has a resistance of 2.4 . What voltage is applied by the batteries if the current in the circuit is
2.5 A?
0.96
V 1.0
V 4.9
V 6.0 V

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Respuesta :

fatouramjaun fatouramjaun · Answer 1 · 2017-05-25T16:27:09+02:00

using V=IR, I is 2.5 and R is 2.4
therefore answer is 2.4 multiply by 2.5 which is equal to 6v

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BarrettArcher BarrettArcher · Answer 2 · 2018-12-20T08:21:55+01:00

Answer : The voltage applied by the batteries is, 6.0 V

Solution : Given,

Resistance of flashlight = 2.4 ohm

Current in the circuit = 2.5 Ampere

Formula used :

[tex]V=IR[/tex]

where,

V = applied voltage

I = current in the circuit

R = resistance of light

Now put all the given values in the above formula, we get

[tex]V=(2.5A)\times (2.4ohm)=6volt=6V[/tex]

Therefore, the voltage applied by the batteries is, 6.0 V