Respuesta :
The solution would be like this for this specific problem:
Area of Circle = 16(π)
= 16 * 3.14
= 50.24
Area of Square = 64
= 64 – 50.24
= 13.76
Area of Square but not on the circular board = 13.76 / 64
= 0.215
Percentage value = 0.215 * 100%
= 21.5%
So, to the nearest percent, the probability that the dart lands inside the square but not on the circular dartboard is 21.5%.
The probability that the dart lands inside the square but not on the circular dartboard is 21 percent.
Probability
The probability of an event is defined as the ratio of the size of the event space to the size of the sample space.
Given information
A dartboard consists of a circle inscribed in a square.
The area of the circle is 16π square centimeters.
The area of the square is 64 square centimeters.
Izzy randomly throws a dart at the square, and it lands inside the square.
Let x be the number event space and y be the sample space.
The value of x is (61- 16π) and y is 64.
The probability is;
[tex]\rm Probability =\dfrac{Event \ space}{Sample \ space}\\\\Probability=\dfrac{64-16\pi }{64}\\\\Probability = \dfrac{64-16(3.14) }{64}\\\\ Probability = \dfrac{64-50.24}{64}\\\\ Probability = \dfrac{13.76}{64}\\\\ Probability = \dfrac{64-50.24}{64}\\\\Probability =0.21\\\\Probability = 0.21 \times 100 \\\\Probability = 21 \ percent[/tex]
Hence, the probability that the dart lands inside the square but not on the circular dartboard is 21 percent.
To know more about probability click the link given below.
https://brainly.com/question/3672687
