Respuesta :
A - getting an even number at least once
A' - not getting an even number at all
[tex] |\Omega|=6^2=36\\
|A'|=3\cdot3=9\\\\
|A|=|\Omega|-|A'|\\
|A|=39-9=27\\\\
P(A)=\dfrac{27}{36}=\dfrac{3}{4}=75\% [/tex]
The probability of getting an even number at least once will be 1/4.
What is probability?
Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
Probability = Number of favorable outcomes / Number of sample
It is given that a fair dice is rolled twice. The probability of getting an even number at least once will be calculated as:-
Number of favorable outcomes = { 2 , 4 , 6 } = 3
It is rolled two times total favorable outcomes = 3 x 3 = 9
Number of samples = 6 x 6 = 36
The probability will be calculated as:-
Probability = Number of favorable outcomes / Number of sample
Probability = 9 / 36
Probability = 1 / 4
Therefore, the probability of getting an even number at least once will be 1/4.
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