so first find the slope of the bondary line
y=mx+b
m=sloe
b=y intercept
seems to have a y intercept at y=-3
b=-3
y=mx-3
another point is (6,0)
input that, remember (x,y)
x=6, y=0 is a point
0=m(6)-3
0=6m-3
3=6m
1/2=m
equation of boundary line is y=1/2x-3
dahsed line so it is > or <
see if it is which one
test y<1/2x-3
find a point in the shaded area and see if it is true
(6,-3)
-3<1/2(6)-3
-3<3-3
-3<0
true
the equation is y<(1/2)x-3
