Answer:
The solutions are (-1, 14) and (6, 7)
Step-by-step explanation:
Given two equations
[tex]y=x^2-6x+7.......(1)[/tex]
[tex]y=-x+13...............(2)[/tex]
we have to solve the above two equations
Substitute the value of y from (2) equation to (1), we get
[tex]-x+13=x^2-6x+7[/tex]
[tex]x^2-5x-6=0[/tex]
By middle term splitting method
[tex]x^2-6x+x-6=0[/tex]
[tex]x(x-6)+1(x-6)=0[/tex]
[tex](x+1)(x-6)=0[/tex]
[tex]x=-1,6[/tex]
(2) ⇒ y=-x+13
when x=-1, y=-(-1)+13=1+13=14
when x=6, y=-6+13=7
Hence, the solutions are (-1, 14) and (6, 7)
