Answer:
So, it does, the points shown on the line would be part of y = −2x.
Step-by-step explanation:
1)The linear function [tex]y=-2x[/tex] is a decreasing one therefore it is graphed from 2nd Quadrant to 4th Quadrant. In addition to this, since is linear parameter b is equal to zero, the line crosses its origin. Finally, its slope is equal to -2.
2)We have (-1,2) and (2,4), pointed out. Linear functions with b=0 are proportional ones. Proportional functions have its slope calculated by:
[tex]k=\frac{y}{x}=\frac{2}{-1}=\frac{4}{-2}\Rightarrow k=-2[/tex]
So, it does, the points shown on the line would be part of y = −2x.