In the circle, mBC=86. The diagram is not drawn to scale

The angle ∠BCP will be equal to 43° for the given diagram.
The circle is defined as the locus of the point traces around a fixed point called the centre and is equidistant from the out trace.
To solve this question we will use the following theorem: "An Angle formed by a chord and a tangent that intersect on a circle is half the measure of the intercepted arc ".
As can be seen from the diagram, the intercepted arc is BC and its angle is.
∠BOC = 86°
By using the theorem,
∠BCP = [tex]\dfrac{1}{2}[/tex] x ∠BOC
∠BCP = [tex]\dfrac{1}{2}[/tex] x 86
∠BCP = 43°
Therefore the angle ∠BCP will be equal to 43° for the given diagram.
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