Potassium fluoride (KF), a salt, has a gram-formula weight of 58.10 grams. How many grams would be needed to mix 1.00 liter of 5.00 molar salt solution? g
If one mole of KF is equal to 58.10 grams (gram-formula weight) then 5 moles should be 5 x 58.10 or 290.5 grams in 1 litre of water. This is taking the molar unit to be the 58.10 grams figure and then just multiplying it by 5 to get the conentration in the 1 liter of water.
