Ans: 25 mM
For example, suppose we take the following concentrations:
Diluted Fe[tex] (NO_{3})_{3} [/tex] =1 ml
1 M KSCN = 5 ml
0.1 M HN[tex] O_{3} [/tex] = 2 ml
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Then, total volume = 8 ml
Now,
final concentration of diluted Fe[tex] (NO_{3})_{3} [/tex] =[tex] \frac{Concentration - of Fe(NO_{3})_{3}*Volume of Fe(NO_{3})_{3}}{Total Volume} \\ \\ [/tex]
given stock solution is 0.2 M
Thus, concentration of diluted solution = [tex] \frac{0.2*1}{8} = 0.025 M = 25 milli M[/tex]
