Find the lowest common denominator of the following fractions.

y+5/6y^2-6 and 7/8y+8

A. 24y 2
B. 24(y 2 - 1)
C. 24(y 2 - 1)(y + 1)

Respuesta :

I believe the answer is B, 24(y^2 - 1)

Answer:

(B) [tex]24(y^2-1)[/tex]

Step-by-step explanation:

Given: The given following fractions are:

[tex]\frac{y+5}{6y^2-6}[/tex] and [tex]{\frac{7}{8y+8}}[/tex]

To find: The lowest common denominator of the given fractions.

Solution: The given following fractions are:

[tex]\frac{y+5}{6y^2-6}[/tex] and [tex]{\frac{7}{8y+8}}[/tex]

Simplifying the above fractions, we get

[tex]\frac{y+5}{6(y^2-1)}[/tex] and [tex]\frac{7}{8(y+1)}[/tex]

Now, the lowest common denominator of the above fractions is:

[tex]24(y+1)(y-1)[/tex]

=[tex]24(y^2-1)[/tex] (using identity [tex]a^2-b^2=(a+b)(a-b)[/tex])

Hence, option (B) is correct