Answer-
[tex]\boxed{\boxed{m\angle EAB=81^{\circ}}}[/tex]
Solution-
Tangent-Chord Angle Theorem
An Angle formed by a chord and a tangent that intersect on a circle is half the measure of the intercepted arc
.
As EF is a tangent to the circle, AB is a chord of the circle.
So, applying the theorem
[tex]m\angle EAB=\dfrac{1}{2}\widehat{ADB}[/tex]
As given that, [tex]\widehat{ADB}=162^{\circ}[/tex]
Putting the value,
[tex]m\angle EAB=\dfrac{1}{2}\times 162^{\circ}=81^{\circ}[/tex]
