The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). What is the standard form of the equation for this line? x – 4y = 8 x – 4y = 2 4x – y = 8 4x – y = 2
hello : the standard form of the equation for this line: x – 4y = 8 because : the line that passes through (–4, –3) and (12, 1) : -4-4(-3) = 8 12-4(1) = 8
