Respuesta :

jaquan13927
If y varies directly as x, 
y = kx 


when y = 48,  x = 6
plugging this in y = kx

48 = k*6 
k = 48/6 = 8.

when x = 2,
y = kx = 8*2 = 16

so I think the expression you're looking for is:
 y = 8*2 or y = (48/6)*2.

Answer

Find out the find the value of y when x is 2 .

To prove

As given

If y varies directly as x .

[tex]y \propto x[/tex]

y = kx

Where  k is the constant of proportionality.

y is 48 when x is 6,

48 = 6k

[tex]k = \frac{48}{6}[/tex]

k = 8

Now calculate the value of y when x is 2 .

y = 8 × 2

y = 16

Therefore the  value of y is 16  when x is 2 .


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