Reactives -> Products
CuO and water are products.
I found this reaction which has CuO and water as products: decomposition of Cu(OH)2.
Cu(OH)2 -> CuO + H2O
Stoichiometry calculus involve the mole proportions you can see in the reaction: When 1 mole of Cu(OH)2 reacts, 1 mole of CuO and 1 mole of H2O are formed.
Considering the molar masses:
Cu(OH)2 = 83.56 g/mol
CuO = 79.545 g/mol
H2O = 18.015 g/mol
Then: When 83.56 g of Cu(OH)2 react, 79.545 g of CuO and 18.015 g H2O are formed.
You should use that numbers in the rule of three:
79.545 g CuO __________18.015 g water
3.327 g CuO__________ x =3.327*18.015 /79.545 g water
x= 0.7535 g water
Answer:
The vaporized water during the reaction is 0.753g.
Explanation:
The mentioned decomposition reaction is;
[tex]\rm CuSO_2\rightarrow CuO+H_2O[/tex]
This means 1mol( 83.56 g) copper hyposulfite decomposes to form 1mol(79.545g) of Copper oxide and 1mol(18.015g) of water.
If 3.327g of CuO is producing which is 26.905 times less than its malar value.
Hence, Water released during the reaction is
[tex]\rm \frac{18.015}{23.908} = 0.753[/tex]
For more details, you can refer to the link:
https://brainly.com/question/3215608?referrer=searchResults
