Respuesta :
To get the vertex of the parabola we proceed as follows;
y=-7(x-4)^2-5
The above can be written as:
y=-7x^2+56x-117
The values of a,b and c are:
a=-7, b=56 and c=-117
x=-b/(2a)
x=-56/(-7*2)=4
but;
y=-7x^2+56x-117
y=-7(4)^2+56(4)-117
y=-5
Thus;
x=4 and y=-5
The vertex will be at point (4,-5)
y=-7(x-4)^2-5
The above can be written as:
y=-7x^2+56x-117
The values of a,b and c are:
a=-7, b=56 and c=-117
x=-b/(2a)
x=-56/(-7*2)=4
but;
y=-7x^2+56x-117
y=-7(4)^2+56(4)-117
y=-5
Thus;
x=4 and y=-5
The vertex will be at point (4,-5)
The coordinate of the parabola vertex will be; (4, -5)
How to find the coordinates of vertex of a parabola?
We are given the parabola equation as;
y = -7(x - 4)² - 5
The above equation can be written as:
y = -7x² + 56x - 117
From general quadratic form of y = ax² + bx + c, we can say that;
a = -7
b = 56
c = -117
x = -b/(2a)
x = -56/(-7 * 2)
x = 4
However;
y = -7x² + 56x - 117
y = -7(4)² + 56(4) - 117
y = -5
Therefore, the vertex will be at point (4,-5)
Read more about Parabola Vertex at; https://brainly.com/question/17987697
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