Respuesta :

To get the vertex of the parabola we proceed as follows;
y=-7(x-4)^2-5
The above can be written as:
y=-7x^2+56x-117
The values of a,b and c are:
a=-7, b=56 and c=-117
x=-b/(2a)
x=-56/(-7*2)=4
but;
y=-7x^2+56x-117
y=-7(4)^2+56(4)-117
y=-5
Thus;
x=4 and y=-5
The vertex will be at point (4,-5)


The coordinate of the parabola vertex will be; (4, -5)

How to find the coordinates of vertex of a parabola?

We are given the parabola equation as;

y = -7(x - 4)² - 5

The above equation can be written as:

y = -7x² + 56x - 117

From general quadratic form of y = ax² + bx + c, we can say that;

a = -7

b = 56

c = -117

x = -b/(2a)

x = -56/(-7 * 2)

x = 4

However;

y = -7x² + 56x - 117

y = -7(4)² + 56(4) - 117

y = -5

Therefore, the vertex will be at point (4,-5)

Read more about Parabola Vertex at; https://brainly.com/question/17987697

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