Respuesta :

mH₂CO₃: (1g×2) + 12g + (16g×3) = 62 g/mol

1 mol --- 62g
0,8 mol -- X
X = 0,8×62
X = 49,6g

Explanation:

It is known that number of moles is equal to the mass divided by molar mass of a substance.

Mathematically,      No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

Since it is given that number of moles is 0.80 mol and molar mass of [tex]H_{2}CO_{3}[/tex] is 62.03 g/mol.

Therefore, we can conclude that mass of [tex]H_{2}CO_{3}[/tex] is as follows.

                 No. of moles = [tex]\frac{mass}{\text{molar mass}}[/tex]

                       0.80 mol = [tex]\frac{mass}{62.03 g/mol}[/tex]

                             mass = 49.62 g

Thus, we can conclude that mass in grams of 0.800 mole of [tex]H_{2}CO_{3}[/tex] is 49.62 g.